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4 years ago

How do I test if a relationship is linear without graphing it?

Mathematics

1 answer:

lbvjy [14]4 years ago

3 0

You need to check if there is a constant rate of change between the values

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van purchased a dvd player on sale. the initial price was $154.30. the price after the discount was $132.17 . what was the perce

likoan [24]

Answer:

86%

Step-by-step explanation:

8 0

4 years ago

How many solutions does this equation have? x = x + 9

Simora [160]

Answer: infinte

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Subtract.<br>(4x^2 + 8x - 2) - (2x^2 - 4x + 3)<br>Enter your answer, in standard form.

vovikov84 [41]

Answer:

$\large\boxed{(4x^2 + 8x - 2) - (2x^2 - 4x + 3)=2x^2+12x-5}$

Step-by-step explanation:

$(4x^2 + 8x - 2) - (2x^2 - 4x + 3)\\\\=4x^2 + 8x - 2 -2x^2 -(- 4x)- 3\\\\=4x^2+8x-2-2x^2+4x-3\qquad\text{combine like terms}\\\\=(4x^2-2x^2)+(8x+4x)+(-2-3)\\\\=2x^2+12x-5$

5 0

3 years ago

A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his s

Hunter-Best [27]

Answer:

d) The difference exists due to chance since the test statistic is small

Step-by-step explanation:

From the given information:

Population mean = 178 cm

the sample mean = 177.5 cm

the standard deviation = 2

the sample size = 25

The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

$H_o: \mu = 178$

Alternative hypothesis:

$H_1: \mu \neq 178$

The t-test statistics is determined by using the formula:

$t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

$t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}$

$t = \dfrac{-0.5}{\dfrac{2}{5}}}$

$\mathbf{t= -1.25}$

Degree of freedom df = n- 1

Degree of freedom df = 25 - 1

Degree of freedom df = 24

At the level of significance ∝ = 0.05, the critical value = 2.064

Decision rule: To reject the null hypothesis if the test statistics is greater than the critical value at 0.05 level of significance

Conclusion: We fail to reject the null hypothesis since the test statistics is lesser than the critical value and we conclude that the difference exists due to chance since the test statistic is small

5 0

3 years ago

Write an equation using four numbers that multiply to 0, neither of which are opposites.

guapka [62]

Answer:

0 x anything = 0

Step-by-step explanation:

Anything multiplied by 0 = 0

4 0

2 years ago