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pshichka [43]
2 years ago
13

Write an equation using four numbers that multiply to 0, neither of which are opposites.

Mathematics
1 answer:
guapka [62]2 years ago
4 0

Answer:

0 x anything = 0

Step-by-step explanation:

Anything multiplied by 0 = 0

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Write a number between 40 and 60. The number is divisible by 6 and has exactly 10 factors.
marshall27 [118]
There is 60 but only jas 9 facrors
6 0
3 years ago
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Part B: In complete sentences, explain how a circle can be used to find the circumcenter of the triangle graphed below.
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

<u><em>Part B:</em></u>

The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.

<u><em>Part C:</em></u>

Coordinates of the midpoint of line BC ( y = - 1 ) are

( \frac{-6+2}{2} , \frac{-1-1}{2} ) = <em>( - 2 , - 1 )</em> and the equation of the line ⊥ to BC is <em>x = - 2</em>

Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r = \frac{BC}{2} = 4

3 0
2 years ago
3) Given the box plot below, what is the lower quartile and upper quartile? *
Allisa [31]

Answer:

A. lower quartile is 3 and upper quartile is 8

im pretty sure but idkk

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If the graph of f(x) = x is shifted up 9 units, what would be the equation of the new graph?
goblinko [34]

Answer:

x+9

Step-by-step explanation:

f(x) = x, going up 9

that is y=x, going up 9

if you wnat to go up, subtract 9 from y

y -9 = x

y=x+9

convert back to f(x)

f(x) = x+9

5 0
3 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
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