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pshichka [43]
2 years ago
13

Write an equation using four numbers that multiply to 0, neither of which are opposites.

Mathematics
1 answer:
guapka [62]2 years ago
4 0

Answer:

0 x anything = 0

Step-by-step explanation:

Anything multiplied by 0 = 0

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A slope of -5 that passes through (2,15)
amm1812

Answer:

y=-5x+25

That is the answe in slope intercept form

8 0
3 years ago
This question has three parts. Answer the parts in order.
nalin [4]

Answer:

The area of the smallest section is A_{1}=100yd^{2}

The area of the largest section is A_{2}=625yd^{2}

The area of the remaining section is A_{3}=250yd^{2}

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

A_{1}=10yd*10yd

A_{1}=100yd^{2}

- Area of the second section:

A_{2}=x^{2} (Eq.1)

- Area of the third section:

A_{3}=width*length

A_{3}=10yd*x (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

A_{1}+A_{2}+A_{3}=975yd^{2}

Replacing values:

100+x^{2}+10x=975

Solving for x:

x^{2}+10x-875=0

x=\frac{-10+\sqrt{100+(4*875)}}{2}

x=\frac{-10+\sqrt{3600}}{2}

x=\frac{-10+60}{2}

x=25

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

A_{2}=25^{2}

A_{2}=625yd^{2}

- From Eq.2:

A_{3}=10*25

A_{3}=250yd^{2}

3 0
3 years ago
I catfished someone and I was being so nice I don’t think I’ve ever been that nice to someone the point is that imma Kermit (mem
Katyanochek1 [597]
Omg don’t catfish it’s so damaging to your own self confidence!
4 0
3 years ago
Find the lowest common denominator 3x^3y^2 and 18xy^3
Katyanochek1 [597]
3x^3y^2=(3)(x)(x)(x)(y)(y)\\\\18xy^3=(3)(3)(2)(x)(y)(y)(y)\\\\Answer:(3)(3)(2)(x)(x)(x)(y)(y)(y)=18x^3y^3
7 0
3 years ago
If pencils sell at 6 for 59 cents how many pencils can be bought for 2.95
Olegator [25]
We already know from the given data that 6 pencils can be bought for 59 cents. We have to determine the number of pencils that can be bought for $2.95.
So
Price of 6 pencils = 59 cents.
Price of 1 pencil = (59/6) cents
                           = 9.83 cents
Now total amount in hand for buying pencils = $2.95
                                                                       = 295 cents
Then the number of pencils that can be bought for 295 cents = (295/9.83)
                                                                                                   = 30.01
So the maximum number of pencils that can be bought for $2.95 is 30 pencils.
4 0
3 years ago
Read 2 more answers
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