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Montano1993 [528]
3 years ago
5

What is the value of x in the figure?

Mathematics
2 answers:
blondinia [14]3 years ago
4 0

Answer:

34 degrees

Step-by-step explanation:

Anika [276]3 years ago
4 0

Answer:

34°

Step-by-step explanation:

given that the x + 56 form a right angle(shown by the box), x + 56 = 90

x = 90-56 = 34

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2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16
Masja [62]

Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}

With this equation, we can factor each equation:

\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}

We can cancel out like terms since they would be dividing each other:

\frac{x-4}{2x-2}

8 0
3 years ago
You are considering developing a regression equation relating a dependent variable to two independent variables. One of the vari
lys-0071 [83]

Answer:

Step-by-step explanation:

a. How many dummy variables are needed to represent the categorical variable?

We need 1 less dummy variable than outcomes for the categorical variable.

categorical variable has 2 outcomes

So, we need 2-1 = 1 dummy variable.

Answer: 1

Note: If our categorical variable had 5 outcomes, we would need 5-1 = 4 dummy variables.

b. Write the multiple regression equation relating the dependent variable to the independent variables.

Note: Depending your your professor, this can be written one of the following ways...

yhat = a + b1 x1 + bx2

yhat = b0 + b1 x1 + b2 x2

yhat = beta0hat + beta1hat x1 + betahat2 x2

where x1 is the ratio variable

and x2 is the dummy variable

c. Interpret the meaning of the coefficients in the regression equation.

b0 = the predicted value of y when x1 and x2 both equal 0.

b1 = the change in y when x1 increases by 1 unit holding x2 constant.

b2 = the predicted difference in y between the two possible outcomes of the categorical variable holding x1 constant.

7 0
3 years ago
What is .2272 as a percent?
Nadusha1986 [10]

Answer:

22.72%

Step-by-step explanation:

you multiply the decimal by 100...ie you move the decimal point to the right twice to get your percent

8 0
3 years ago
Read 2 more answers
A data set has a maximum of 84, a minimum of 34, a median of 52.5, an upper quartile of 64, and a lower quartile of 44. Which st
Akimi4 [234]

Answer:

A box and whiskers plot has a box whose endpoints are the interquartile range (25th percentile and 75th percentile), has a dividing line at the median, aka the 50th percentile, and whiskers that extend out to the minimum and the maximum of the data.

Let's sort the info for ease of reference:

min 34, lower quartile 44, median 52.5, upper quartile 64, max 84.

OK, let's go through the statements.

A. The box will go from 44 to 64.

The box goes from the lower quartile to the upper quartile, TRUE

B. A line dividing the box will be at 54.

There's no 54 mentioned at all, FALSE

C. The left whisker will go from 34 to 52.5.

The left whisker goes from the minimum to the lower quartile, 34 to 44 here, FALSE.

D. The right whisker will go from 44 to 84.

The right whisker goes from the upper quartile to the max, 64 to 84 here.  FALSE

If this could help, please mark me brainliest! Have an awesome day too!

4 0
2 years ago
The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot
Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

brainly.com/question/27270616

#SPJ4

       

       

4 0
2 years ago
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