The answer is 21.
I am not sure if you're looking for the answer, or the steps... get back to me foor help.
Answer:
2/9
Step-by-step explanation:
Simplify 80°/360°
Is the 10 taking away 5 or was it meant to me 10.5 ?
The ratio of similar areas is the square of the ratio of the scale factor.
Circle R's sector is (5/2)² = 25/4 the area of Circle Q's sector.
Answer:
59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.
Step-by-step explanation:
Step 1
Express the angle of inclination as follows;
Tan∅=H/R
where;
∅=angle of inclination
H=vertical rise
R=distance of run
Step 2
Determine the angle inclination when;
H=3 feet
R=2 feet
replacing;
Tan∅=(3/2)=1.5
∅=Tan^(-1)(1.5)
∅=56.31°
Determine the angle inclination when;
H=5 feet
R=3 feet
replacing;
Tan∅=(5/3)=1.67
∅=Tan^(-1)(1.67)
∅=59.03°
59.03° is greater than 56.31°' This means that the sliding pole that rises 5 feet for every 3 feet of run making an angle of inclination of 59.03° is steeper than the angle of inclination made by a sliding pole that rises 3 feet for every 2 feet run.
