Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Suppose you are given the two functions <span>f (x) = 2x + 3</span><span> and </span><span>g(x) = –x2 + 5</span><span>. Composition means that you can plug </span><span>g(x)</span><span> into </span><span>f (x)</span><span>. </span>
170.5 is the answer from the TI-84
a trade in is closely related to a down payment because it reduces the amount financed.
<span><span><span>x2</span>+2x−22=0</span><span><span>x2</span>+2x-22=0</span></span>Use the quadratic formula to find the solutions.<span><span><span>−b±<span>√<span><span>b2</span>−4<span>(ac)</span></span></span></span><span>2a</span></span><span><span>-b±<span><span>b2</span>-4<span>(ac)</span></span></span><span>2a</span></span></span>Substitute the values <span><span>a=1</span><span>a=1</span></span>, <span><span>b=2</span><span>b=2</span></span>, and <span><span>c=−22</span><span>c=-22</span></span> into the quadratic formula and solve for <span>xx</span>.<span><span><span>−2±<span>√<span><span>22</span>−4⋅<span>(1⋅−22)</span></span></span></span><span>2⋅1
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