Answer:
A. EG = √3 × FG
D. EG = √3/2 × EF
E. EF = 2 × FG
Step-by-step explanation:
∵ tan 60 = √3
∵ tan60 = EG/GF
∴ EG/GF = √3
∴ EG = √3 × GF ⇒ A
∵ m∠F = 60°
∵ sin60 = √3/2
∵ sin 60 = EG/EF
∴ √3/2 = EG/EF
∴ EG = √3/2 × EF ⇒ D
∵ cos60 = 1/2
∵ cos60 = GF/EF
∴ GF/EF = 1/2
∴ EF = 2 × GF ⇒ E
Answer:1.414 rounded to the nearest thousandths
Step-by-step explanation:
Hello there,
From Point A to Point B Peter traveled roughly 30 miles in 30 minutes.
From Point B to Point C Peter traveled roughly 130 miles in 2 hours and 30 minutes.
From Point C he didn't move in distance but the hours moved so c is out.
From Point C to Point D, Peter traveled roughly 180 miles in 3 hours.
Therefore D Peter had the fastest interval at D.