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shepuryov [24]
3 years ago
14

A 2-column table with 9 rows. The first column is labeled year with entries 1970, 1975, 1980, 1985, 1990, 1995, 2000, 2005, 2010

. The second column is labeled pounds of trash with entries 3.25, 3.25, 3.66, 3.83, 4.57, 4.52, 4.74, 4.69, 4.44.
The table shows the average number of pounds of trash generated per person per day in the United States from 1970 to 2010. Use the statistics calculator to calculate the mean and median. Round the answers to the nearest hundredth.



Median =



Mean =
Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Answer:

Median: 4.44

Mean: 4.11

On edge

Step-by-step explanation:

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Simplify.<br> -5x^4(-3x^2+4x-2)
Amiraneli [1.4K]

Answer:

3x^6 - 4x^5 + 2x^4

Step-by-step explanation:

Given

-5x^4 ( -3x^2 + 4x - 2)

Step 1 : open the bracket with -5x^4

-5x^4 * -3x^2= 15x^6

Hint: - * - = +

x^4 * x ^2 = x^ 4+2 = x^6

-5x^4 * + 4x = - 20x^5

Hint: - * + = -

x^4 * x = x^4 + 1 = x^5

(x is always raise to the power of 1 but we don't write it or less it is greater than 1 e.g. 2 , 3 ,4, ..........)

-5x^4 * -2 = 10x^4

Hint: - *- = +

Let's combine the answers

15x^6 - 20x^5 + 10x^4

We can look for a factor that can go through as in that can divide all without a reminder

Factors of

15 - 3 * 5

1 * 15

20 - 4 *5

2 *10

1 * 20

10 - 2*5

1 * 10

Since the factor of 5 is common in all, so we are using 5 to divide through

15x^6 - 20x^5 + 10x^4

Using 5 to divide through

15x^6 / 5 - 20x^5 / 5 + 10x^4 / 5

= 3x^6 - 4x^5 + 2x^4

4 0
4 years ago
The scale in a drawing is 2 cm : 5 m. What are the length and width of the actual room? Find the area of the actual room. 10 cm
Radda [10]
10/2= 5 so 5: 5 x 5 so the length is 25. 6/3 = 2  so 2: 2 x 5 = 10.
Area is length times width. 25 x 10= 250
3 0
4 years ago
Give me the answer pls! thank u
Anettt [7]

Answer:

6, 12, 15, 9

Step-by-step explanation:

answer is in the picture

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!! IM CONFUSED AND GOT IT WRONG
wariber [46]

Answer:

Area of the gym floor = 100.8 square meters

Step-by-step explanation:

Area of the gym floor = Area of rectangle A + Area of rectangle B - Area of the overlap

Area of rectangle A = 105 square meters

Area of rectangle B = 8.4 square meters

Area of the overlap = \frac{3}{25}\times (\text{Area of rectangle A})

                                = \frac{3}{25}\times 105

                                = 12.6 square meters

Area of the gym floor = 105 + 8.4 - 12.6

                                    = 100.8 square meters

Therefore, area of the gym floor is 100.8 square meters.  

4 0
3 years ago
Read 2 more answers
∫∫(x+y)dxdy ,d là miền giới hạn bởi x²+y²=1
igor_vitrenko [27]

It looks like you want to compute the double integral

\displaystyle \iint_D (x+y) \,\mathrm dx\,\mathrm dy

over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.

Convert to polar coordinates, in which <em>D</em> is given by the set

<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}

and

<em>x</em> = <em>r</em> cos(<em>θ</em>)

<em>y</em> = <em>r</em> sin(<em>θ</em>)

d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>

Then the integral is

\displaystyle \iint_D (x+y)\,\mathrm dx\,\mathrm dy = \iint_D r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \int_0^{2\pi} \int_0^1 r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \underbrace{\left( \int_0^{2\pi}(\cos(\theta)+\sin(\theta))\,\mathrm d\theta \right)}_{\int = 0} \left( \int_0^1 r^2\,\mathrm dr \right) = \boxed{0}

3 0
3 years ago
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