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SOVA2 [1]
3 years ago
7

A cylinder has a height of h inches and a diameter of 3 inches. Give the expression of the volume of the cylinder in cubic inche

s.
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0
Expression of volume = 1/3 × pi × radius
(squared ) × height

radius = diameter / 2
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Are the two figures similar? If so, give the similarity ratio of the smaller figure to the larger figure.
Dovator [93]

Answer:

yes 1:2

Step-by-step explanation:

Set up the ratio

Cylinder(1) = 6.4:3.2

Cylinder(2) = 4:2

Is 6.4/3.2 = 4/2?

12.8 = 12.8!

So yes.

5 0
3 years ago
Can you help me please.
saul85 [17]
45 is the answer
hope this helps :)
8 0
3 years ago
Read 2 more answers
I’ll pay $20 in cashapp for whoever can do this
raketka [301]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
Помогите, пожалуйста
Cerrena [4.2K]

1.

6 - 2х² = 6 - 2(-8)² = 6 - 2(64) = 6 - 128 = -122

2.

\displaystyle\tt a^{11}\cdot a^{14}=a^{11+14}=a^{25}\\\\a^{18}:a^{14}=a^{18-14}=a^4\\\\(a^5)^4=a^{5\cdot4}=a^{20}\\\\(5x)^4=5^4\cdot x^4=625x^4\\\\\bigg(\frac{a}{3}\bigg)^6=\frac{a^6}{3^6}=\frac{a^6}{729}

3.

\displaystyle\tt \frac{14^{16}\cdot14^{6}}{14^{21}}=14^{16+6-21}=14^1=14\\\\\\ \frac{7^{8}\cdot7^{5}}{7^{11}}=7^{8+5-11}=7^2=49\\\\\\ (12^2-11^2)^2+(6^5+2^9)^0=(144-121)^2+1=23^2+1=529+1=530

4.

\displaystyle\tt 3^{8x}=81\\\\3^{8x}=3^4\\\\8x=4\\\\x=\frac{4}{8}=\frac{1}{2}=0.5

5.

\displaystyle\tt \frac{64^{6}}{4^{4}\cdot4^{16}}=\frac{(4^3)^{6}}{4^{4+16}}=\frac{4^{3\cdot6}}{4^{20}}=\frac{4^{18}}{4^{20}}=\frac{1}{4^{2}}=\frac{1}{16}

5 0
4 years ago
Luis bought stock at $83.60. The next day, the price increased $15.35. This new price changed by -4 and 3/4 (mixed number) the f
olga_2 [115]
For the  answer to the question above,
$83.60 Increase 15.35 dollars 83.60 = $98.95
So the new price will be = $98.95
%4.75 Of $98.95 = $4.700125 Rounded it off to about $4.70
$98.95- $4.700125 = $94.249875 Rounded to about $94.25

The Final stock price was $94.249875 or about $94.25

I hope my answer helped you. Have a nice day!
5 0
3 years ago
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