<span>a.
</span>Do you
have sufficient funds to estimate the population mean for the attribute of
interest with a 95% confidence interval 4 units width? Assume that sd= 12
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.96)^2*(12)^2/ (2)^2
n=
138.297 rounded up to 139
<span>There
is not enough funds for this one
since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.</span>
b.
90% confidence interval
n= {[(Zalpha/2)^2]*[sd]^2}/
se^2
n=
(1.645)^2*(12)^2/ (2)^2
n=98
There is enough
funds since 98 pieces for 10 a piece is equal to 980.
Y=1 1/4(1.25)x +9, add 8x to each side and then divide each side by 6
Do you remember when you were learning about the "Least Common
Multiple" of two numbers, and you were wondering why you had to learn
it, because you were so sure that you'd never need to use it ? Do you
remember that ?
Well, HERE's where you get to use it. This question is just looking for
the LCM of 6 and 15 . THAT's how many days it will be before you get
homework in both subjects on the same day again.
(It's not 90 days, and it's not 60 days.)
Answer:
No is correct
Step-by-step explanation:
convert 2/3 into 6ths
4/6 = 8/12
so no, non of them equal to 4/8
2x² - 3xy
2(1)² - 3(1)(2)
2(1) - 3(2)
2 - 6
-4
