All categories

3 years ago

What is the equation in point−slope form of the line passing through (1, 2) and (2, 5)? (5 points)

Mathematics

1 answer:

Jlenok [28]3 years ago

8 0

Slope is 3 so the equation is y-2=3(x-1) in point slope form as y-y1 =m (x-x1)

You might be interested in

The function y = f(x) is graphed below. What is the average rate of change of the

Serjik [45]

The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

<h3>What is the average rate of change?</h3>

The average Rate of Change of the function f(x) can be calculated as;

$f(x) = \dfrac{f(b) - f(a)}{b-a}$

Interval -3 ≤ x ≤-1

a = -3, b = -1

f(a) = f(-3) = -20

f(b) = f(-1) = 0

Step 2: Find Average

$f(x) = \dfrac{f(b) - f(a)}{b-a}\\\\\\f(x) = \dfrac{f(-1) - f(-3)}{-1-(-3)}\\\\\\f(x) = \dfrac{0 - (-20)}{2}\\\\f(x) = 10$

Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

Learn more about average rate;

brainly.com/question/20784578

#SPJ1

3 0

1 year ago

A submarine changes its position by −7 meters every second. What is the change in the submarine's position after 300 seconds?

Hoochie [10]

If you take -7*300 is should equal -2100

5 0

3 years ago

Read 2 more answers

Find distance in parsec

olganol [36]

1. 200 Parsecs, 652.312 Light years 2. 8 Parsecs, 26.09248 Light years ; Use this formula, p=1/P(parallax), to solve the equation. Then multiply 3.26156 (light years per parsec) by the number of parsecs.

1. p= 1/0.005 = 200*3.26156 = 652.312

200 Parsecs, 652.312 Light years

2. p=1/0.125 = 8*3.26156 = 26.09248

8 Parsecs, 26.09248 Light years

4 0

3 years ago

Estimate the product<br> A)Close to 40<br> B)Close to 004<br> C)Close to 0.4<br> D)Close to 4

PtichkaEL [24]

Close to 0.4 aka c :))

7 0

3 years ago

Read 2 more answers

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

3 years ago