2 years ago

Help with geometry asap quiiiik

1 answer:

3 0

1. Seg AC congr seg DB          1. Given
2. Seg BE congr seg CE                   2. Given
3. <BCA congr <CBD                        3. In a triangle, if two sides are congruent,
opp angles are congruent
4. Seg BC congr seg BC                4. Congr of segs is reflexive
5. Tr. ACB congr Tr DBC                  5. SAS
6. Seg AB congr seg DC                   6. CPCTC

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Solve quadratic formulax^2-4x+3=0

bekas [8.4K]

The general formula for a equation of the form:

$ax^2+bx+c=0$

is:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

$\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}$

then: