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ExtremeBDS [4]
2 years ago
9

How many sevenths are there in two wholes?

Mathematics
1 answer:
schepotkina [342]2 years ago
7 0

Answer:

14

Step-by-step explanation:

7 times 2 = 14

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2.34 x 10^65   + 9.2 x10^66  
vivado [14]

Answer:

9.434 X 10^66

Step-by-step explanation:

2.34 X 10^65  +  9.2 X 10^66    (First, you have to manipulate the exponents to bring them to the same index, i.e. the same power)

We can say that 2.34 X 10^65 = 0.234 X 10^66

Now that the indexes are equivalent, we can proceed to add the two bases together.

0.234 X 10^66  +  9.2 X 10^66

= (0.234  +  9.2) X 10^66

= 9.434 X 10^66

3 0
3 years ago
A concession stand at a baseball game sells 3 apples for $2.00. How can you find the cost for 10 apples?
Angelina_Jolie [31]
You would do $2.00 ÷ 3 = $0.67
10 × $0.67 = $6.70

10 apples would cost $6.70

HOPE THIS HELPED :)
6 0
3 years ago
Read 2 more answers
Their win percentage was 40, then how many matches did they play in all!
Neko [114]

Answer:

14400

Step-by-step explanation:

X - X × 75%=3600

X - X × \frac{75}{100} = 3600

X - \frac{3X}{4} = 3600

\frac{4X-3X}{4} = 3600

\frac{X}{4} = 3600

X = 3600 × 4

X = 14400

3 0
2 years ago
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
3 years ago
Answers for both boxes please ​
sleet_krkn [62]

Answer:

x = -5  y = -3

Step-by-step explanation:

-3x + 2y = 9

multiply the 2nd equation by 3 to set it up for elimination

3(x - 3y)= 3(4)

3x-9y = 12

so now combine both to add

-3x + 2y = 9

3x - 9y = 12

Adding both gives you

-7y = 21

divide both by -7 and you get

y = -3

and you substitute y back into equation to get x

x - 3 (-3) = 4   gives you

x + 9 = 4

x = 4 - 9

x = -5

7 0
2 years ago
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