Answer:
If you round two decimal places, it should be 9.
Step-by-step explanation:
Answer:
2y + 3 = 4y + 2; y = 1/2
Step-by-step explanation:
to find this equation we can use the ys and the 1s to create an equation
so
in the left side
there are 2 ys and 3 1s
your equation is
2y + 3
on the other side
it is
4 ys and 2 1s
so
4y + 2 is your equation
then yo uset them equal to each other
2y + 3 = 4y + 2
if you must solve
subtract 2y and 2 from both sides
1 = 2y
then divide both sides by 2
y = 1/2 is your answer
Step-by-step explanation:
Given : A triangle with side lengths 
To find : Prove that when x > 1, it is a right triangle. Use the Pythagorean theorem and the given side lengths to create an equation. Use the equation to show that this triangle follows the rule describing right triangles. Explain your steps ?
Solution :
For right triangle the Pythagorean theorem is to be satisfied.
i.e. 
Here, 
Substitute the values,



LHS=RHS
It is a right triangle.
The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable
Answer:
9.55
Step-by-step explanation:
11.30 - 1.75 = 9.55
Simple maths.