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GREYUIT [131]
2 years ago
10

Marsha recorded the time it took seven children of different ages to run one lap around the track.

Mathematics
2 answers:
max2010maxim [7]2 years ago
7 0
The answer is C. 205.
vlada-n [284]2 years ago
5 0
Answer: C

Reasoning: There is a 40s difference between the age of 4 and 8 meaning 6 most likely would be in the center of that, which also means it’d be about half of 40. So with that we subtract 20 from 225 and thus giving us the closest length of time it should take Marsha’s 6 year old niece to run one lap, 205s.
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3 years ago
(x+5)(x+4)(x-2)-(x^2+11x-9)(x+1)+5x^2
Luda [366]
(x+5)•(x+4)•(x-2)•(x2+11x-9)•(x+26)
STEP
2
:
Equation at the end of step 2

(((x+5)•(x+4)•(x-2))•(x2+11x-9))•(x+26)
STEP
3
:
Equation at the end of step 3

((x+5)•(x+4)•(x-2)•(x2+11x-9))•(x+26)
STEP
4
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Trying to factor by splitting the middle term

4.1 Factoring x2+11x-9

The first term is, x2 its coefficient is 1 .
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Step-1 : Multiply the coefficient of the first term by the constant 1 • -9 = -9

Step-2 : Find two factors of -9 whose sum equals the coefficient of the middle term, which is 11 .

-9 + 1 = -8
-3 + 3 = 0
-1 + 9 = 8

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step
4
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