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3 years ago

WHO EVER ANSWERS CORRECTLY GETS BRAINYEST!

Mathematics

2 answers:

Leto [7]3 years ago

8 0

First simplify

1/2=1

1/8=1/4

In one hour a quarter(fourth) of the field is watered, in 4 hours the field is completely watered

Vaselesa [24]3 years ago

6 0

It will take 4 hours because to get the 1/8 to a whole you have to multiply by 8. and 1/4*8=8/4=2 hours

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(-6x+3)+(5x-4) If you in the 7th grade or up you can answer this question

Otrada [13]

Answer:

-1x + -1

Step-by-step explanation:

(-6x+3)+(5x-4)

-1x + -1

7 0

3 years ago

A cheetah ran 275 feet in 3.23 seconds. How fast did the cheetah run in miles per hour? Round your answer to the nearest whole m

yawa3891 [41]

First we convert feet into meters, since 1 feet is 0.3048 m: 275 feet * 0.3048 = 83.82m.

Then we do: 83.82m / 3.23s = 25.9504644 m/s.

Then we convert that into miles per hour by 2.23694, so we do:

25.9504644 * 2.23694 = 58.0496318.

Then we round it to 58 mph.

So the answer is: The cheetah was running at 58 mph.

Hope this helped! c:

6 0

3 years ago

What is the diameter, circumference, and area of a circle that has the radius of 7?

user100 [1]

Answer:

the diameter is: 14

the circumference is: C≈43.98

the area is: A≈153.94

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

T What's the circumference of a circle with a diameter of 45 centimeters? A. 141.4 centimeters B. 6,361.7 centimeters C. 282.7 c

Sphinxa [80]

C=pid
d=45
c=45pi
aprox pi=3.14
c=141.3

A is answer

5 0

3 years ago

Solve the equation 2^(2x+1)+8=17×2^x.

myrzilka [38]

Oooh, looks fun

ok
erm
we might want to know some properties
$(x^m)(x^n)=x^{m+n}$
$(a^b)^c=a^{bc}$
if $a^m=a^n$ where a=a, then assume m=n

$2^{2x+1}=(2^{2x})(2^1)$
so
$(2^{2x})(2)+8=17(2^x)$
$(2^{2x})(2)+2^3=17(2^x)$
$(2^x)^2(2)+2^3=17(2^x)$
minus 17*2^x both sides
$(2^x)^2(2)+2^3-17(2^x)=0$
use u subsitution, u=2ˣ
$(u)^2(2)+2^3-17(u)=0$
solve $2u^2+8-17u=0$
or
$2u^2-17u+8=0$
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
$2^3=2^x$
3=x

and
$\frac{1}{2}=2^x$
$2^{-1}=2^x$
-1=x

x=-1 and 3
neat problem

8 0

3 years ago