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vfiekz [6]
3 years ago
9

What is the sum of 4.2•10^5 and 5.3• 10^5

Mathematics
1 answer:
sleet_krkn [62]3 years ago
3 0
If my math is correct, it should be 950,000
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PLEASE HELP!!!!!!!!!!!!! ​
Kamila [148]

Answer:

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Step-by-step explanation:

The equation shows that n - 2 (2 less than a number) and then = 6

4 0
3 years ago
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The mean caloric intake of an adult male is 2800 with a standard deviation of 115. To verify this information, a sample of 25 me
erma4kov [3.2K]

Answer:

Step-by-step explanation:

We would use the t- distribution.

From the information given,

Mean, μ = 2950

Standard deviation, σ = 115

number of sample, n = 25

Degree of freedom, (df) = 25 - 1 = 24

Alpha level,α = (1 - confidence level)/2

α = (1 - 0.98)/2 = 0.01

We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01

The corresponding z score is 2.492

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

2950 ± 2.492 × 115/√25

= 2950 ± 2.492 × 23

= 2950 ± 57.316

The lower end of the confidence interval is 2950 - 57.316 =2892.68

The upper end of the confidence interval is 2950 + 57.316 = 3007.32

The solution is correct.

8 0
3 years ago
Any suggestions for a word problem for the equation : 5/12 * 1/6?
n200080 [17]
Thomas had 5/12 of a pie. his friend, Katelyn ate 1/6 of his pie. How much is left?
8 0
3 years ago
.6(2k - 3) = 3(4k + 5)<br> Hellppp pleaseee
muminat

Answer:

Step-by-step explanation:

.6(2k-3)=3(4k+5) foil

1.2K-1.8=12k+15 subtract 1.5k from both sides

-1.8=10.8k+15 subtract 15 from both sides

-16.8=10.8k divide by 10.8

k= -1.5

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2 years ago
A sample proportion of 0.18 is found. To determine the margin of error for this statistic, a simulation of 100 trials is run, ea
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<span>±0.04 is the correct answer</span>
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3 years ago
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