This can be solved by factoring.
First, set the expression equal to zero.

Then, find two the factors of

whose sum is

.

Split

into these two factors.

Next, factor by grouping.

By the Zero Product Property, set each factor equal to zero.


These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree

has exactly

complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done.
Your answers are -2 and 1/3. There are two real roots.
Answer:
No it is not a good prediction. Theoretical probability says that the answer would be 30 of the 60 (30/60) rolls would be even numbers.
Step-by-step explanation:
The probability of rolling an even number on a fair six sided die is 3/6 or 1/2 when simplified.
if john rolls the die 60 times, multiply the theoretical probability (1/2) by the number of rolls
(1 ÷ 2) x 60 = 30
∴ theoretical probability says that john would roll an even number 30 out of the 60 rolls
I hope this was helpful :-)
Answer: 3.5
Step-by-step explanation: divide 49 by 14
46/100
The numeric value is in the hundredths to covert it to a fraction you'll need to keep the same value so the fraction will be 46/100
If you're looking to simplify the fraction will be 23/50
Answer:
Tan C = 3/4
Step-by-step explanation:
Given-
∠ A = 90°, sin C = 3 / 5
<u>METHOD - I</u>
<u><em>Sin² C + Cos² C = 1</em></u>
Cos² C = 1 - Sin² C
Cos² C = 
Cos² C = 
Cos² C = 
Cos C = 
Cos C = 
As we know that
Tan C = 
<em>Tan C =
</em>
<em>Tan C =
</em>
<u>METHOD - II</u>
Given Sin C = 
therefore,
AB ( Height ) = 3; BC ( Hypotenuse) = 5
<em>∵ ΔABC is Right triangle.</em>
<em>∴ By Pythagorean Theorem-</em>
<em>AB² + AC² = BC²</em>
<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>
<em>AC² = 5² - 3²</em>
<em>AC² = 25 - 9</em>
<em>AC² = 16</em>
<em>AC ( Base) = 4</em>
<em>Since, </em>
<em>Tan C =
</em>
<em>Tan C =
</em>
<em>Hence Tan C =
</em>
<em />