Answer:
Step-by-step explanation:
#3
(i)
- P(A and B) = P(A) * P(B) = 3/8*2/7 = 3/28
(ii)
- P(A or B) = P(A) + P(B) - P(A and B) = 3/8 + 2/7 - 3/28 = 1/56(21 + 16 - 6) = 31/56
(iii)
- P(not A and not B) = P(not A) * P(not B) = (1 - 3/8)*(1 - 2/7) = 5/8*5/7 = 25/56
<u>Another way:</u>
- P(not A and not B) = 1 - P(A or B) = 1 - 31/56 = 25/56
#4
Outcomes with two fair coins: TT, TH, HT, HH
Outcomes with normal dice: 1 to 6
a)
- P(odd number) = 3/6 = 1/2
b)
- P(two heads and an even number) = 1/4*3/6 = 1/8
c)
- P(head and tail) = 1/2
- P(prime) = 3/6 = 1/2 (primes are 2, 3 and 5)
- P(head, tail and prime) = 1/2*1/2 = 1/4
d)
- P(two tails and odd number) = 1/4*3/6 = 1/8
Answer:
120/5
24 inches.
Step-by-step explanation:
Answer:
You did not complete the question :(
Step-by-step explanation:
Answer:
Explanation:
The theoretical probability, P (A), of an event, A, is:
- P(A) = number of outcomes of event A / total number of possible outcomes
For 10 cranberry and 15 strawberry juices, the number of outcomes for two strawberry juices are:
- Combination of 15 strawberry juices chosen in two:

The total number of possible outcomes is:
- Combination of 25 juices chosen in two:

Thus, the probability of randomly picking two strawberry juices is:
- P (two strawberry juices) = 105/300 = 7/20
Note that you can obtain it as the product of the probabilities that the first juice is a strawberry juice and the second juice is also strawberry juice:
