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3 years ago

How do I find the interval for a frequency table

1 answer:

3 0

First you need to know how to calculate the class interval;

Calculating the class interval using the following formula:

Class interval = range ÷ number of classes. If you have 15 classes of income in the distribution of income example, work out 30 ÷ 15 = $2 billion.

Anyways, back to your question how you would find the interval for a frequency table is yeah think I explained it right.

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This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the t

sergey [27]

Because it is an isosceles triangle, the two longer sides are the same length. Therefore multiply 6.3 times 2.
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8 0

3 years ago

Read 2 more answers

Simplify please help

aleksandr82 [10.1K]

Answer:

4√10xy/32y is the answer. (I think)

5 0

2 years ago

The graph of the piecewise function f(x) is shown what is the domain of f(x)

Rom4ik [11]

The domain of a function is where we have a value for x.

Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}

We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle

So, our x can vary between 1 and 5, but can't be 5.

8 0

3 years ago

Can someone please solve this, tell me which one goes where in order.

sasho [114]

Total discount for 10 group tickets = 10 · 0.05t

Amount of discount per ticket = 0.05t

Number of tickets = 10

Cost of buying 10 single tickets = 10t

Solution:

Cost for single ticket = t dollars

Discount percent per ticket = 5%

Number of tickets bought = 10

Total discount for 10 group tickets = Number of tickets × Discount amount

= 10 × 0.05t

Total discount for 10 group tickets = 10 · 0.05t

Amount of discount per ticket = 5%t

= $\frac{5}{100}$ t

= 0.05t

Amount of discount per ticket = 0.05t

Number of tickets = 10

Cost of buying 10 single tickets = 10t

4 0

3 years ago

What is the area of the shaded region on the graph shown?

Sindrei [870]

Answer:

As Doris Day said: Good morning to you

Answer 27/2

Step-by-step explanation:

$f(x)=-x^3+5x\\F(x)=-\dfrac{x^4}{4} +\dfrac{5x^2}{2} \\F(2)=\dfrac{-16}{4}+\dfrac{20}{2} =6\\\\F(-1)=\dfrac{-1}{4} +\frac{5}{2} =\dfrac{9}{4} \\g(x)=\dfrac{3x^2}{2}+\dfrac{x}{2}-5\\\\G(x)=\dfrac{x^3}{2} +x^2-5x\\\\G(2)=4+1-10=-5\\\\G(-1)=\dfrac{-1}{2} +\dfrac{1}{4} +5=\dfrac{19}{4} \\\\\int\limits^2_{-1} {(f(x)-g(x))} \, dx =F(2)-G(2)-(F(-1)-G(-1))\\\\=11+\dfrac{5}{2} =\dfrac{27}{2}$

5 0

3 years ago