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3 years ago

¿Cuál es el valor de 0.1561 redondeado a la décima más cercana?

Mathematics

1 answer:

Alik [6]3 years ago

3 0

Answer: 0.2

Step-by-step explanation: Necesitamos ajustar la estimación de 0.1561 al décimo más cercano.

El número después del decimal es el número en el décimo lugar. Considere el número a un lado del lugar de las décimas y utilice el número para decidir si se reunirán o seguirán siendo el equivalente. Observe que el número a un lado del décimo lugar es mayor o equivalente a 5 o menos de 5. En el caso de que ese número sea más digno de mención o equivalente a 5, en ese punto el número se reunirá aún en la remota posibilidad de que ese número es menor de 5, en ese momento el número no se reunirá. Permanecerá igual.

Consideremos el número dado 0.1561

El número en el lugar de las décimas es 1

El número después del punto de las décimas es 5 (que es más prominente o equivalente a 5)

De esta manera, el número se reunirá en 0,2

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Step-by-step explanation:

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Answer:

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<h3>Answer: C) I and II only</h3>

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Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

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Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$

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Part III

$\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\$

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