All categories

3 years ago

Whaaaaaat is true about the sum of the two polynomials

1 answer:

4 0

the result of adding two polynomials will always be another polynomial. A polynomial is an algebraic expression made up of the sum of monomials, which are products of numbers (coefficients) and variables in positive integer exponents.

You might be interested in

If StartFraction pi Over 2 EndFraction less than t less than pi , which of the following is true?

oksian1 [2.3K]

Answer:

b. cosine t less than 0 and cotangent t greater than 0

Step-by-step explanation:

We have the following relation

$\frac{\pi }{2} < t$

if we apply the cosine function in the relation we get:

$cos\frac{\pi }{2}$

$-1$

the cosine of t is between 0 and -1 then (cosine t less than 0)

If we now apply cotangent function in the relation:

$cotan\frac{\pi }{2}$

$0$

This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0

5 0

3 years ago

Consider a series system composed of 4 separate components where each component has a 30% chance of failing. Assume each compone

Marina86 [1]

Answer:

16.15% probability that exactly 3 of them would function

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of each system working:

4 components, which means that $n = 4$

Each has a 30% probability of failing, so $p = 1 - 0.3 = 0.7$

For the system to work, all 4 components have to work. This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401$

0.2401 probability of a system working.

If you have 7 of these systems, what is the probability that exactly 3 of them would function?

Now 7 systems, so $n = 7$

0.2401 probability of a system working.

We have to find P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{7,3}.(0.2401)^{3}.(0.7599)^{4} = 0.1615$

16.15% probability that exactly 3 of them would function

5 0

3 years ago

Dan drove 737 miles in 11 hours. At the same rate, how many miles would he drive in 13 hours?

kari74 [83]

Answer:

871

Step-by-step explanation:

737 divided by 11 is 67, so thats how many miles he drives per hour

67 times 13 is 871

3 0

3 years ago

Read 2 more answers

___ tens 15 ones = 6 tens 5 ones

Bezzdna [24]

The answer would be 5 tens.

4 0

3 years ago

Read 2 more answers

What is the solution to the equation √8x=√4+2x?

dolphi86 [110]

Answer:

0.3333333333333...........

7 0

4 years ago