Answer:
a. 
b. 
Step-by-step explanation:
a. 
A mixed fraction of the form 



b. 
A mixed fraction of the form 




Hence, the answer.
Answer:
No Real Solutions.
Step-by-step explanation:
√(x-5)=8√(x-2)
Square on both sides,
(√(x-5))^2=(8√(x-2))^2
or,(x-5)=64(x-2)
or,x-5=64x-128
or,-5+128=64x-x
or,123/63=x
Therefore, x=41/21
If you plug x=41/21 in √(x-5)=8√(x-2) you do not get equals, so the problem has no real solutions.
The line passes through two points that have the same x-coordinate.
It is a vertical line. To find the slope of a line, use any two points. Subtract the y-coordinates. Subtract the x-coordinates in the same order. Then divide the difference of the y-coordinates by the difference of the x-coordinates. Since in this case, the x-coordinates are both -6, the difference between the x-coordinates is zero. Division by zero is not defined, so the slope of this line is undefined. You can't write its equation in point-slope form, because there is no slope for this line.
The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
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I believe the answer would be $13,320.
Hope this helps ;}