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olya-2409 [2.1K]
3 years ago
10

3 miles 1,254 feet = how many feet

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
17,094 feet if you add them hope this helps
Veseljchak [2.6K]3 years ago
3 0

Answer: 17,094 feet

Step-by-step explanation:

5280 ft. in 1 mile

5280 x 3= 15,840

15,840+1,254= 17,094 ft.

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If 2.5 is a root of the equation 2x^2+5x−q=0, what are the possible values of q?
bulgar [2K]

Answer:

q = -2510 +5 = \pm \sqrt{5^2-4*2*q} \\ 225 = 25-8q \\\\8q = -200 \rightarrow q = -\frac {200}8 = -25

Step-by-step explanation:

Grab the generic solution of the equation. \frac 52 = \frac{-5 \pm \sqrt{5^2-4*2*q}}{2*2}. Let's isolate the radical, and square both sides.10 +5 = \pm \sqrt{5^2-4*2*q} \\ 225 = 25-8q \\\\8q = -200 \rightarrow q = -\frac {200}8 = -25

4 0
3 years ago
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The sum of twice a number and 15 is -42
satela [25.4K]
Assume that the number is n.
sum of twice the number and 15 means that you will first multiply the number by 2 then add 15.
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2n + 15 = -42
2n = -42-15
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5 0
3 years ago
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Rebecca draws two triangles on this coordinate plane.
anzhelika [568]

Answer:

The answer is below

Step-by-step explanation:

From the image attached, the coordinates of triangle ABC are at A(-5, 4), B(-5,7) and C(-2, 7)

a) If a point O(x,y) is rotated 90° clockwise, the new coordinate is O'(y, -x)

If triangle ABC is rotated 90° clockwise, its new coordinate is at:

A'(4, 5), B'(7, 5) and C'(7, 2)

The coordinate of A"B"C" is A"(2,5), B"(5,5), C(5,2)

Hence the transformation used to map A'(4, 5), B'(7, 5) and C'(7, 2) to A"(2,5), B"(5,5), C(5,2) is (x - 2, y + 0). Hence comparing with (x + h, y + k) gives:

h = -2, k = 0

b) If a point O(x,y) is reflected across the y = -x line, the new coordinate is O'(-y, -x)

If triangle ABC is reflected across y = -x, its new coordinate is at:

A'(-4, 5), B'(-7, 5) and C'(-7, 2)

The coordinate of A"B"C" is A"(2,5), B"(5,5), C(5,2)

8 0
3 years ago
15 trucks can carry 26,850 kg weight. Find the weight carried by one truck.
nadya68 [22]

\huge\underline{\underline{\boxed{\color{blueviolet}{ANSWER}}}}

★ 15 trucks can carry 26,850 kg weight

★ We've to find the weight carried by one truck

\huge \pink {\overline{ \quad \quad \quad \quad \quad \quad \quad\quad \quad}}

\sf{Number  \: of \:  trucks = 15 }

\sf{Weight  \: carried  \: by  \: one \:  truck = \frac{26,850Kg}{15} }

\sf  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:                  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:= 1790Kg

Therefore , the weight carried by one truck is 1790 kg

7 0
2 years ago
Party Supplies Inc. Sells metallic ballons for $2 each and Helium ballons for 3:50 per bunch. Yesterday the sold 36 more metalli
zzz [600]

Answer:

Metallic Balloons = 74

Bunches of Helium Balloons = 38

Step-by-step explanation:

The question basically asks for the number of "metallic balloons" sold and the number of bunches of "helium balloons" sold.

We will do it in our way. Let B be number o metallic balloons and H be number of bunches of Helium balloons.

Since Metallics cost 2 each and Heliums cost 3.5 per bunch and totaled sales is 281, we can write and equation as:

2B + 3.5H = 281

and, since they sold 36 MORE metallic than helium ,we can write an equation as:

B - 36 = H

We can put 2nd equation in 1st one and solve for B first:

2B + 3.5H = 281\\2B + 3.5(B-36) = 281\\2B+3.5B-126=281\\5.5B=407\\B = \frac{407}{5.5}\\B=74

B = 74

Now, we find H:

H = B - 36

H = 74 - 36 = 38

H = 38

3 0
3 years ago
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