The sum of three numbers is 132 . the third number is 7 less than the first. the second number is 3 times the third. what are th
e numbers?
1 answer:
X+y+z = 132
x = 7+z
y = 3z
(7+z)+3z+z = 132
5z = 132-7
z = 125/5
z = 25 <=====
x = 7+z
x = 7 + 25
x = 39 <=====
y = 3z
y = 3 × 25
y = 75 <=====
hope it helps :)
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