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3 years ago

I’m haveing a hard time explaining why D is the right answer please help

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

Because d actually collects data about what the people want.

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A gardener has 10 pounds of soil.He used 5/8 of the soil for his garden.How many pounds of soil did he use in the garden?How man

dybincka [34]

Answer:

6.25 pounds used

3.75 pounds lelft

Step-by-step explanation:

10 pounds/8=1.25 pounds

1.25 x 5 = 6.25pounds used

10 - 6.25 = 3.75 pounds left

5 0

4 years ago

lana66690 [7]

Answer:

I don't know

Step-by-step explanation:

Because you are in college and that's what it says!!

5 0

3 years ago

For Caroline’s birthday, her mom took her and 4 friends to a water park. Caroline’s mom paid $40 for 5 student tickets. What was

melomori [17]

Answer:

each kid would be 9$ a ticket

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

How to find extreme values of a function.

baherus [9]

Answer:

See below

Step-by-step explanation:

Extreme values of a function are found by taking the first derivative of the function and setting it equal to 0. To determine if it's a minimum or maximum, we set the second derivative equal to 0 and determine if its positive or negative respectively.

Let's do $f(x)=3x^4+2x^3-5x^2+7$ as an example

By using the power rule where $\frac{d}{dx}(x^n)=nx^{n-1}$ , then $f'(x)=12x^3+6x^2-10x$

Now set $f'(x)=0$ and solve for $x$ :

$0=12x^3+6x^2-10x$

$0=2x(6x^2+3x-5)$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-3\pm\sqrt{3^2-4(6)(-5)}}{2(6)}$

$x=\frac{-3\pm\sqrt{9+120}}{12}$

$x=\frac{-3\pm\sqrt{129}}{12}$

$x=-\frac{3}{12}\pm\frac{\sqrt{129}}{12}$

$x=-\frac{1}{4}\pm\frac{\sqrt{129}}{12}$

$x_1=0,x_2\approx0.6965,x_3=-1.1965$

By plugging our critical points into $f(x)$ , we can see that our extreme values are located at $(0,7)$ , $(0.6965,5.956)$ , and $(-1.1965,2.565)$ .

The second derivative would be $f''(x)=36x^2+12x-10$ and plugging in our critical points will tell us if they are minimums or maximums.

If $f''(x)>0$ , it's a minimum, but if $f''(x)$ , it's a maximum.

Since $f''(0)=-10$ then $(0,7)$ is a local maximum

Since $f''(0.6965)=15.822>0$ , then $(0.6965,5.956)$ is a local minimum

Since $f''(-1.1965)=27.18>0$ , then $(-1.1965,2.565)$ is a global minimum

Therefore, the extreme values of $f(x)=3x^4+2x^3-5x^2+7$ are a global minimum of $(-1.1965,2.565)$ , a local minimum of $(0.6965,5.956)$ , and a local maximum of $(0,7)$ .

Hope this example helped you understand! I've attached a graph to help you visualize the extreme values and where they're located.

7 0

3 years ago

Solve for d.

zysi [14]

5 hope that helps answer

8 0

4 years ago

Read 2 more answers