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DiKsa [7]
3 years ago
12

Plss help because idk understand plsssssss heeeeelllllllppppppp

Mathematics
1 answer:
Anika [276]3 years ago
5 0

Answer:

Only B

Step-by-step explanation:

As it says in the graph, the situation we're dealing with are hours to meters. So, A would not be the correct answer. B shows proper use of both hours and meters with the right values. C is incorrect because the answer is B.

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What is the value of s in the equation 3r = 10 + 5s, when r = 10
Bad White [126]
3r = 10 + 5s , <span>r = 10
plug in the value of "r" into the equation:
3(10) = 10 +5s
30 = 10 + 5s
subtract 10 from both sides:
20 = 5s
divide both sides by 5:
4 = s
s = 4</span>
8 0
4 years ago
Help please and thanks will mark as brainliest
algol13
11)
3x = 180
x = 60

12)

6x + 18 = 180
6x = 162
x = 27
3 0
3 years ago
23. A grid shows the positions of a subway stop and your house. The subway stop is located at (-5, 2) and your house is located
Sindrei [870]
(-5, 2)(-9,9)
D = √( (x2 - x1)^2 + (y2 - y1)^2 )
D = √( (-9+5)^2 + (9 - 2)^2 )
D =√( (-4)^2 + (7)^2 )
D = √( 16 + 49 )
D = √65
D = 8
7 0
4 years ago
A police officer claims that the proportion of accidents that occur in the daytime (versus nighttime) at a certain intersection
Roman55 [17]

Answer: -1.78

Step-by-step explanation:

As per given description, we have

Population proportion : p=0.35

Sample size : n= 500

Sample proportion : \hat{p}=\dfrac{156}{500}=0.312

Test statistic for population proportion :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\=\dfrac{0.312-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{500}}}\\\\=-1.78146747757\ \ \text{(Simplified)}\\\\\approx-1.78

Hence, the test statistic for this hypothesis test for a proportion= -1.78

3 0
4 years ago
The perimeter of a ractangle is 28 units what is the value of w
saveliy_v [14]

Answer:

W=5

Perimeter=2(L+W)

2(L+W)=28

2(2W-1+W)=28

2(3W-1)=28

6W=30

W=5

                                                                                                                                                 

5 0
3 years ago
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