Here are Babe Ruth's home run totals for the New York Yankees during the years 1920 - 1934:54, 59, 35, 41, 46, 25, 47, 60, 54, 4
6, 49, 46, 41, 34, 22Which of the following is a box-and-whisker plot for this data set?
2 answers:
Given data is 54, 59, 35, 41, 46, 25, 47, 60, 54, 46, 49, 46, 41, 34, 22
Arranging it in increasing order:
22 25 34 35 41 41 46 46 46 47 49 54 54 59 60
Number of data items, n=15.
Finding Median, First Quartile, and Third Quartile
22 25 34 35 41 41 46 46 46 47 49 54 54 59 60
Now finding First Quartile from set: 22 25 34 35 41 41 46
Q₁ = middle term i.e. 35
Now finding Third Quartile from set: 46 47 49 54 54 59 60
Q₃ = middle term i.e. 54
So we have Q₁ = 35, M = 46, and Q₃ = 54. Lower bound is 22 and Upper bound is 60.
While drawing the given data on number line and marking First quartile, Median, Third quartile on number line. We can clearly observe that option A matches with given data points.
Hence, option A i.e. Box-plot A is the correct choice.
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Answer:
Step-by-step explanation:
I suggest looking lessons on it online if you don't understand... It's hard to do your work especially if you don't understand it. Or if your online, go to past lessons or something.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The probability that there exist 60 or more defected children is
Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence
Step-by-step explanation:
From the question we are told that
in every 1000 children a particular genetic defect occurs to 1
The number of sample selected is
The probability of observing the defect is mathematically evaluated as
The probability of not observing the defect is mathematically evaluated as
The mean of this probability is mathematically represented as
Substituting values
The standard deviation of this probability is mathematically represented as
Substituting values
the probability of detecting defects can be represented in as normal distribution like
in standardizing the normal distribution the normal area used to approximate is the right of 59.5 instead of 60 because x= 60 is part of the observation
The z -score is obtained mathematically as
The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve
Note: We are looking for the area to the right i.e 60 or more
The total area under the curve is 1
So
