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3 years ago

24m^2n+30mn^2+18mn, a sweet challenge!

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

24m^2n+30mn^2+18mn

Factor 6mn ( Greatest Common Factor) out of the 3 terms:

6mn(4m) + 6mn(5n) + 6mn(3)

Factor 6mn out of the first 2 terms:

6mn(4m + 5n +3)

Brums [2.3K]3 years ago

6 0

Answer:

6mn (4m + 5n + 3).

Step-by-step explanation:

The Greatest Common Factor is 6mn , so we have:

24m^2n+30mn^2+18mn

= 6mn (4m + 5n + 3) (answer).

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2 1/8 divided by 2 =

muminat

⇒ Solutions

Make mixed fraction to improper fraction
= 17/8 + 2/1

Make same denominators
<span>= ((17 × 1) + (2 × 8)) / (8 × 1) </span>

Simplify
= (17 + 16) / 8

Simplify (17 + 16) / 8<span> </span>
= 33/8

Mixed Fraction
= 4 1/8

4 0

4 years ago

Read 2 more answers

The value of the digit 9 is 2,107,954

astraxan [27]

The value of the digit 0 is 10 thousand.
What you have to do is break down the numbers so since there is no 0 in 954, then you would move on to the next 3 sets of numbers of which, if the number was just 107, you could see that the 0 is in the tens place and since it is actually 107,000, then you would say that the 0 is in the ten thousands place.

8 0

4 years ago

CALCULUS:

slamgirl [31]

Answer:

$E(p)=\frac{p^2}{40-p^2}$

E(3) = 0.29

2. See Below

Step-by-step explanation:

According to the formula we would need the derivative, so lets first calculate the derivative of f(p) given.

The rules to use would be $f(x)=ax^n\\f'(x)=nax^{n-1}$

Also, remember to use chain rule if there is a function inside a function. So we differentiate the "inside" function again.

Now, lets differentiate:

$f(p)=\sqrt{40-p^2}\\f(p)=(40-p^2)^{\frac{1}{2}}\\f'(p)=\frac{1}{2}(40-p^2)^{\frac{1}{2}-1}*(-2p)\\f'(p)=\frac{1}{2}(40-p^2)^{-\frac{1}{2}}*(-2p)\\f'(p)=-\frac{p}{\sqrt{40-p^2}}$

Now, the E(p):

$E(p)=-\frac{pf'(p)}{f(p)}\\E(p)=-\frac{p*(-\frac{p}{\sqrt{40-p^2}})}{\sqrt{40-p^2}}\\E(p)=\frac{p^2}{40-p^2}$

We find E(3) by substituting 3 into "p":

$E(p)=\frac{p^2}{40-p^2}\\E(3)=\frac{3^2}{40-3^2}\\E(3)=\frac{9}{31}\\E(3)=0.29$

When E(p) = 1, it means the price elasticity of demand is "1". It is the called Unitary Elastic Demand. It means that for every unit change in price, there is the same unit change in demand. The changes of demand and price are proportional to each other.

7 0

3 years ago

The random variable X = the number of vehicles owned. Find the expected number of vehicles owned. Round answer to two decimal pl

Lelechka [254]

Answer:

The expected number of vehicles owned to two decimal places is: 1.85.

Step-by-step explanation:

The table to the question is attached.

$E(X) =$ ∑ $xp(x)$