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3 years ago

Given the following exponential function, identify whether the change represents

Mathematics

1 answer:

lutik1710 [3]3 years ago

6 0

I'm assuming the function given is y = 9300(0.991)^x

If so, then the base of the exponent 0.991 is in the form 1+r

1+r = 0.991

r = 0.991-1

r = -0.009

The negative r value indicates a percent decrease.

Specifically it is a 0.9% decrease since 0.009 = 0.9/100 = 0.9%

Any time you have a percent decrease like this, the exponential function is undergoing decay.

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What is the largest multiple of 36 that can be written with each digit 0-9 exactly once?

antoniya [11.8K]

Answer:

Not sure

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

The sum of two integers is 627, and the larger number is 27 more than 7 times the smaller number. Find the two integers.

Alex777 [14]

Answer:

75 and 552 =627

Step-by-step explanation:

First=x

Second 7x+27

x+ 7x+27= 627

8x+27=627

8x=600

x=75

75*7+27 =525

525+27 = 552

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3 years ago

The fitness center held a weight loss competition in which 128 people participated. The amount of weight loss was normally distr

iris [78.8K]

Answer:

Step-by-step explanation:

Given :

Sample size, n = 128

Mean, μ = 18

Standard deviation, σ = 5.4

Number of people who lost atleast 15 pounds :

The Zscore = (x - μ) / (σ)

Zscore = (15 - 18) / 5.4

Zscore = - 3 / 5.4

Zscore = - 0.5555

P(Z < - 0.555) = 0.28945

Number of people who lost atleast 15 pounds :

0.28945 * 128 = 37.0496

= 37 people

3 0

2 years ago

six coins in your pocket: 5 cents, 10 cents, 20 cents, 50 cents, $1, $2. How many different sums of money can you make?

TEA [102]

Answer:

You can make 64 different sums (which includes a sum of $0 using none of the coins).

Step-by-step explanation:

The number of sums you can make is equal to:

⁶C₀ + ⁶C₁ + ⁶C₂ + ⁶C₃ + ⁶C₄ + ⁶C₅ +⁶C₆ = 1 + 6 + 15 + 20 + 15 + 6 + 1 = 64

3 0

3 years ago

Rebecca has 12 photos she wants to hang side by side on her wall.A. If she only wants to display 8 of the photos, in how many wa

Mariana [72]

If she will choose 8 from 12 photos, the total number of ways she can choose is given by a combination of 12 choose 8, since the order of the photos doesn't matter.

The formula for a combination of n choose p is:

$C(n,p)=\frac{n!}{p!(n-p)!}$

For n = 12 and p = 8, we have:

$C(12,8)=\frac{12!}{8!(12-8)!_{}}=\frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4!}=\frac{12\cdot11\cdot10\cdot9}{4\cdot3\cdot2}=495$

So there are 495 ways.

If she wants to arrange the 12 photos, the total number of ways is given by the factorial of 12:

$12!=12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2=479001600$

There are 479,001,600 ways.

Since 10 photos already have specific places, we need to calculate the number of ways to arrange the other two photos in the two remaining places.

In this case, there are only 2 ways of organizing the remaining two photos:

Photo 1 first, photo 2 last, or photo 1 last and photo 2 first.

6 0

1 year ago