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3 years ago

Danny had $116 to spend on nine books. After buying them he had $72 left. How much did each book cost?

Mathematics

1 answer:

denpristay [2]3 years ago

7 0

4.88
-subtract 116-72
-divide by 9
-round

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4xy- 72 = 3w solve for y

Mashcka [7]

Answer:

y= $\frac{3w}{4x}$ + $\frac{18}{x}$

Step-by-step explanation:

Hope this helps. Plz give brainliest.

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3 years ago

4) Solve ∆ABC, a = 2.5 cm, c = 3.6 cm, and ∠A = 43°. Begin by sketching and labelling

mezya [45]

The length of b and angle B and C are 3cm, 45 degrees and 79 degrees respectively.

<h3>How to determine the parameters</h3>

To determine the angles and length of sides, we use the sine rule

The sine rule is thus:

$\frac{sin A}{a} = \frac{sin B}{b} = \frac{sin C}{c}$

Given;

a = 2. 5cm

c = 3. 6cm

∠A = 43°

Let's find angle C

$\frac{sin 43}{2. 5} = \frac{sin C}{3. 6}$

cross multiply

0. 682 × 3. 6 = sin C × 2. 5

sin C = 2. 4552/ 2. 5

C = $sin^-^1(0. 982)$

C = 79°

To find length of b

$b= \sqrt{c^2 - a^2}$

substitute the values

$b = \sqrt{3.6^2 - 2. 5^2}$

$b = \sqrt{6. 71}$

b = 2. 59 cm

b = 3cm

To find angle B, we have

$\frac{sin 43}{2. 5} = \frac{sin B}{2. 59}$

cross multiply

0. 682 × 2. 59= sin B × 2. 5

sin B = 0. 7065

$B = sin^-^1(0. 7065)$

B = 45°

Hence, the length of b and angle B and C are 3cm, 45 degrees and 79 degrees respectively.

Learn more about sine rule here:

brainly.com/question/12827625

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1 year ago

Given cos theta=4sqrt2/7 find sin theta

m_a_m_a [10]

Answer:

$sin \theta=\sqrt{17}/7$

Step-by-step explanation:

<h3>Given</h3>

$cos \theta=4\sqrt{2}/7$

$sin \theta$

<h3>Solution</h3>

Use identity:

$sin^2x+cos^2x=1$

Substitute and find:

$cos^2 \theta=(4\sqrt{2}/7)^2$
$cos^2 \theta=16*2/49=32/49$

$sin \theta=\sqrt{1-cos^2 \theta} = \sqrt{1-32/49} =\sqrt{17/49} =\sqrt{17}/7$

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The P right there you put = -3/7 after it

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Setler [38]

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