3 years ago

If we need exactly 2,000 pieces of 3.5" in length, how many 8' boards are needed for 2,000 pieces?

Mathematics

1 answer:

Kaylis [27]3 years ago

7 0

Total length of boards needed = 2000*3.5 = 7,000.

Total number of 8' boards needed = 7000/8 = 875 answer

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Pepsi [2]

Answer:

$x = 54$

$y = 0.225$

Detailed steps:

We know that the number of total events is

$n = 80$

and that the probability of a certain event E (for example, "<em>the enemy drops two objects</em>") is computed as the number of times event E occurred, divided by the total of events N=80.

Then:

$0.675 = \frac{x}{80}$

$x = 80 \times 0.675 = 54$

and

$y = \frac{18}{80} = 0.225$

We can verify by checking that adding all probabilities sums up to one.

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Step-by-step explanation:

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