Answer:
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<span>Suppose 2x + y = 15 -----eq 1
. x + 3y = 20 -----eq 2.
Multiplying eq (1) by 1 and (2) by 2 and subtracting the result
We have: 2x + y = 15 and 2x +6y =40.If we subtract, we have y - 6y = 15 - 40.
So we have -5y = -25. y is 5. Substiting into eq (1), we have 2x + 5 = 15. 2x = 15-5 =10 Hence X =5.Hence option B is the correct option.</span>
Answer:
A. 
B. 
C. 
D. 
Step-by-step explanation:
A. To solve the first part of the problem we must replace
in the function 
So:

B. In part B we must find the inverse function of 
To find the inverse function do 

Now clear the variable x.

Replace x with y.

Finally

C. Now we take the inverse function found above and replace 

D. Now we substitute
in the original function.

(8c)^2+7c
(8c)^2=64c^2
so that..
64c^2+7c
factor out c
c(64c+7)
Subtract a number from the next number.
39 - 45 = -6
Answer: B. -6