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Ronch [10]
3 years ago
13

Help me please !!!!!!!!

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

y=5/3x

this is because f(x)=x is one of (identity function) the 12 basic functions and when you multiply it it will shift it on the y axis

If you were to do y=x+5/3 it would make a horizontal shift to the left 5/3

So the unit your on is mostly about knowing the number located in the function that will make the graph shift different ways

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Madison is making party flavors she wants to make enough flavors so each guest gets the same number of flavors she knows there w
bazaltina [42]

Answer:


Step-by-step explanation:

To find the least number of party favors, we have to consider the number of guests.


In this case, there are two possibilities—6 or 8.


For 6: 6, 12, 18, 24 (Add 6 to each number)

For 8: 8, 16, 24 (Add 8 to each number)


Now in both series, the least number (that is in common) is 24. Hence, Madison should make at least 24 party favors.




7 0
3 years ago
((4)/(3v))-((1)/(v))=((v+2)/(2v^2))
Lerok [7]

Step-by-step explanation:

sper că te-am ajutat

5 0
3 years ago
What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y
PSYCHO15rus [73]

Step-by-step explanation:

\sqrt{5 {x}^{8} {y}^{2}  }  \times  \sqrt{10 {x}^{3} } \times  \sqrt{12y}   \\  \\  =   {x}^{4} y \sqrt{5}  \times x \sqrt{10x}  \times 2 \sqrt{3y}  \\  \\  = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y}  \\  \\  =  2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y}  \\  \\ =  2 {x}^{5} y  \times 5\sqrt{ 2x \times 3y}   \\  \\  = 10 {x}^{5} y \sqrt{6xy}  \\

4 0
3 years ago
What is inequalities?<br> What is the form?
SIZIF [17.4K]

Answer: In mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size

Step-by-step explanation:

3 0
3 years ago
"Lito had some marbles. He gave ½ of his marbles plus 1 to Felix, ½ of the remaining marbles plus 1 to Ces, and ½ of the last re
Nuetrik [128]

let

x-------> total amount of marbles at the beginning


we know that

1) He gave ½ of his marbles plus 1 to Felix

(1/2)*x+1=(x+2)/2 (Felix's marbles)

remaining=x-[(x+2)/2]-----> [2x-x-2]/2------> (x-2)/2


2)½ of the remaining marbles plus 1 to Ces

(1/2)*[(x-2)/2]+1=[(x-2)/4]+1-----> (x+2)/4 (Ce's marbles)

remaining=[(x-2)/2]-[(x+2)/4]-----> [2x-4-x-2]/4------> (x-6)/4


3) ½ of the last remaining marbles plus 1 to Pedro

(1/2)*[ (x-6)/4]+1=[(x-6)/8)+1------> (x+2)/8 (Pedro's marbles)

remaining=[(x-6)/4]-[(x+2)/8]------> [2x-12-x-2]/8-----> (x-14)/8


4)If Lito had 1 marble left for himself

so

the last remaining is equal to 1

(x-14)/8=1-----> x-14=8------> x=22 marbles


Verify

(x+2)/2 (Felix's marbles)------> (22+2)/2=12

(x+2)/4 (Ce's marbles)------> (22+2)/4=6

(x+2)/8 (Pedro's marbles)---> (22+2)/8=3

Lito's marbles------------------> 1

total=12+6+3+1=22--------> is ok


therefore


the answer is

the total amount of marbles at the beginning was 22

4 0
3 years ago
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