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iogann1982 [59]

3 years ago

5

a test has 20 questions it award 3 points is the answer is correct and takes away 1 point if the answer is incorrect . what inte

ger represents the amount of points the student lost?

1 answer:

Alex73 [517]3 years ago

6 0

Answer:

1(20-x)

Step-by-step explanation:

let the number of correct answers be x

so wrong will be 20-x

1 mark cancelled from each question

therefore,

1(20-x) will be the answer

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Answer:

1/4 clove

Step-by-step explanation:

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3 years ago

What is the ratio of drivers to cars in a stock car race?

adoni [48]

It would be a 1-1 ration because there is 1 driver for every stock car

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3 years ago

48. Line h passes through the point (4, 12) and is parallel to line k.

Misha Larkins [42]

Answer: <em>y = 3/4 x + 8</em>

Step-by-step explanation: First you must find the slope of line k.

<em>y2 - y1</em>

<em>m = -----------</em> <em>The slope is 3/4</em>

<em> </em><em>x2 - x1</em>

Since the two lines are paralell you know that line h has the same slope.

Next you must find the y-intercept by replacing x and y with the values given by the point.

<em>y = 3/4x + ? -----> 12 = 3/4(4) + ?</em>

<em> 12 = 3 + 8</em>

The y-intercept is 8

Your equation for line h is <em> </em><em>y = 3/4 x +8 </em>

<em></em>

<em>Hope this was helpful!</em>

4 0

2 years ago

Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and

uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

The foci are 10 units to either side of the center, so c = 10 and $c^2 = 100$
The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

Since the intercepts are 6 units to either side of the center, then a = 6 and $a^2 = 36.$

$Then, a^2+b^2=c^2\\b^2=100-36=64$

Therefore, substituting $a^2 = 36.$ and $b^2=64$ into the standard form

$\frac{x^{2}}{a^2} - \frac{y^{2}}{b^2}=1\\We \: have:\\ \dfrac{x^{2}}{36} - \dfrac{y^{2}}{64}=1$

4 0

3 years ago

Need math help please!

algol [13]

Answer:

AAS

Step-by-step explanation:

The triangles are given 2 congruent corresponding angles and 1 congruent corresponding side. So the only answer that would make sense would be the AAS Theorem.

3 0

3 years ago