Answer:
a) negative
b) -7/6
Step-by-step explanation:
The x value increased, but the y value decreased so the line goes down and has a negative slope
(y₁-y₂)/(x₁-x₂) is the slope where (x₁,y₁) and (x₂,y₂) are points on the line
(4-(-3))/(-1-5)=7/-6
The number of student more passed the retake, when the students need a 65 in order to pass the test is 8.
<h3>What is box and whiskers plot?</h3>
Box plot is the way of representation of data which gives the graphical image of the data set to understand better. In this the data is represented with the help of quartile.
- A.The difference in the median grade-
The median of first test is 60 while the second test is 80. Thus, the difference is,

- B. Compare the percent of students who got at least a 60 on the original test to those that got at least a 60 on the retake.
The student, who got at least 60 in first test, falls in the second half of the plot. Thus, the 50% of students got atleast 60% marks. In the retake test, all 100% student got at least 60 on test.
- C. If the students need a 65 in order to pass the test, how many more passed the retake?
In the first test 1/4 are passed while in second test 3/4 students are passed and got the marks 65 or more than this, Thus the number of student pass more in this test,

Thus, the number of student more passed the retake, when the students need a 65 in order to pass the test is 8.
Learn more about the box and whiskers plot here;
brainly.com/question/9559392
#SPJ1
Answer:
16.5 hours
Step-by-step explanation:
Here is the explanation. As Hye drinks 4/3 gallons of water in 11/2 hours, we have a constant rate. There are 12 thirds in 4, so we are trying to find how long it takes Hye to drink 12/3 gallon. In this case, 4/3x3=12/3, so we multiply 11/2 by 3 as well, which gives us 33/2 hours. 33/2 in decimal form is 16.5 hours. Hope it helps!
Answer:
A.10
B.10
C. 10,000
D. 8 hours
Step-by-step explanation:
Firstly, we should know that the numbers are labeled 0-9.
A. 10 digits
B. We already took one digit , but we still have 10 choices left again as numbers can be repeated.
C. For the first number, we have 10C1 choices since we are selecting 1 out of 10 numbers. This is the case for all the 3 renaming numbers. Hence the total number of possible passwords are
(10C1)^4 = 10,000 possible password combinations
D. That is (10,000*3)/60 in minutes = 500 minutes = 500/60 = 8.3333 , approximately 8hrs