The graph of proportional relationship is the straight line in Quadrant I and start in the origin.
Look at the picture.
Happy New Year from MrBillDoesMath!
Answer:
i ^ (2n) = (i^2)^n = (-1)^n = -1 if n is odd and = 1 if n is even
i ^ (2n+1) = i^(2n)* i = -1 * i = -i if n is odd and = 1*i = i if n is even
Not sure if this answers your question but hopefully pushes you n the right direction.
Thank you,
MrB
Answer:
C
Step-by-step explanation:
49x² + 28xy + 4y² ← is a perfect square of the form
(ax + by)² = a²x² + 2abxy + b²y²
49 = 7² ⇒ a = 7 and 4 = 2² ⇒ b = 2
2ab = 2 × 7 × 2 = 28
Hence
49x² + 28xy + 4y² = (7x + 2y)²
with factor 7x + 2y ⇒ C
6.4 is the answer you are looking for! Hope that helps :))
