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ikadub [295]
3 years ago
6

What is the solution of the equation 3 (×+2)=×+11

Mathematics
2 answers:
Ugo [173]3 years ago
6 0

3(x + 2) = x + 11

3x + 6 = x + 11

3x - x = 11 - 6

2x = 5

x = 5 / 2 or x = 2.5


Hey Braniac! Thanks for your question! Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~

Ainat [17]3 years ago
5 0

3(x+2) = x+11

3x+6 = x+11

3x-x = 11-6

2x = 5

x = 5/2  OR

x = 2.5

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Answer:

BGC=180-90

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Elenna [48]

Answer: the answers 190

Step-by-step explanation:

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Please asap<br>for 10 points!​
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<h3>Given:</h3><h3>Large cone:</h3>
  • r= 8 cm
  • h= 20 cm
<h3>Small cone:</h3>
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<h3>Note that:</h3>
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\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

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V= \frac{1}{3}×\pi×{4}^{2}×10

V= 167.5516082 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

\boxed{V= 167.55 \: {cm}^{3}}

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

V= \frac{1}{3}×\pi×{8}^{2}×20

V= 1340.412866 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

\boxed{V=1340.41 \: {cm}^{3}}

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

V= 1340.41-167.55

\large\boxed{V= 1172.86 \: {cm}^{3}}

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>



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