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zepelin [54]
3 years ago
15

What is the longest stick that can be placed within a box whose inside dimension are 24 inches, 30 inches, and 18 inches?

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

42.42 inches

Step-by-step explanation:

Given the dimension of the box are 24 inches, 30 inches, and 18 inches.

Considering the box is in rectangular in shape.

We also know that longest part of the box is the diagonal.

∴ lets calculate the diagonal to find longest stick that can be placed within a box.

Diagonal= \sqrt{a^{2}+b^{2}+c^{2} }

Where a,b,c are the dimensions of the box.

Diagonal= \sqrt{24^{2} +30^{2}+18^{2} }

⇒ Diagonal= \sqrt{576+900+324}

⇒ Diagonal= \sqrt{1800}

⇒ Diagonal= 42.42 inches

Hence, 42.42 inches longest stick that can be placed within a box.

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3 years ago
If f(x)=7-3x and g(x)=3x-7, what is the value of f(1)-g(1)?
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Substitute 1 for x in each of your equations.

f(x)=7-3x
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Do the same for g(x)
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6 0
3 years ago
PLEASE HELP ASAPPPPP
sveticcg [70]

Answer:

506.7 cm²

Step-by-step explanation:

The amount of cardboard needed would be the surface area of the cone,

S= pi(r)(l+r) where r is the radius and l is the slant height.

You can find l using the Pythagorean theorem. l²=r²+h² which is l²=6²+20² and you get l = √436.

Plug r and l into the equation: S = 6pi(√436 + 6) = 506.7 cm²

Let me know if you have any questions about my steps!

4 0
2 years ago
How can you tell when a quadratic equation has two identical, rational solutions?. a:when the radicand is negative. b:when the r
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3 years ago
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