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zepelin [54]
3 years ago
15

What is the longest stick that can be placed within a box whose inside dimension are 24 inches, 30 inches, and 18 inches?

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

42.42 inches

Step-by-step explanation:

Given the dimension of the box are 24 inches, 30 inches, and 18 inches.

Considering the box is in rectangular in shape.

We also know that longest part of the box is the diagonal.

∴ lets calculate the diagonal to find longest stick that can be placed within a box.

Diagonal= \sqrt{a^{2}+b^{2}+c^{2} }

Where a,b,c are the dimensions of the box.

Diagonal= \sqrt{24^{2} +30^{2}+18^{2} }

⇒ Diagonal= \sqrt{576+900+324}

⇒ Diagonal= \sqrt{1800}

⇒ Diagonal= 42.42 inches

Hence, 42.42 inches longest stick that can be placed within a box.

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G(x)=-x^2-1-2x<br> f(x)=x+5<br> Find (g-f)(x)
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<u>Step-by-step explanation:</u>

Step 1:

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3 years ago
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Step-by-step explanation:

1.

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First equation: Your equation is given.

Second equation: Distribute by multiplying every number in the parentheses by the number outside it.

3rd equation: Combine like terms by adding 4x to both sides.

4th equation: Combine like terms by subtracting 14 from both sides.

5th equation: Divide both sides by -2, the coefficient of x.

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Answer:

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Step-by-step explanation:

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