Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer:
1
Step-by-step explanation:
√12
√10
√5
divide all by 6
1a (you don’t necessarily need to include the 1, so you can just put “a” if you’d like).
Answer:
4
Step-by-step explanation:
Step 1:
6x - 8 = 4x Equation
Step 2:
6x = 4x + 8 Add 8 on both sides
Step 3:
2x = 8 Subtract 4x on both sides
Step 4:
x = 8 ÷ 2 Divide
Answer:
x = 4
Hope This Helps :)
