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ella [17]
3 years ago
11

A researcher wants to study the relationship between salary and gender. She randomly selects 297 individuals and determines thei

r salary and gender. Can the researcher conclude that salary and gender are dependent?
Mathematics
1 answer:
padilas [110]3 years ago
4 0

Answer:

The researcher cannot conclude that salary and gender are dependent.

Step-by-step explanation:

A dependent variable is a variable, for example "Salary" that depends on an independent variable, e.g. "Gender."  Salary is the dependent variable while gender is the independent variable.  This means that the value of salary changes in relation to the gender and not vice versa.  Two variables become dependent if they change based on another independent variable that is operating on them.  In this research, the researcher is not trying to measure gender but the relationship between salary and gender.  To achieve her purpose, she shows that salary depends on gender and not that gender depends on salary.

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3 years ago
Read 2 more answers
The equation f(x)= 2x-9 translate 6 units up is g(x)=
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Btw I got this answer from gauth math
answer: 2x -3

Explanation
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7 0
2 years ago
A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
Aneli [31]

a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
3 years ago
Help What is the graph???
marin [14]

We are given

y=\frac{x^2-4x+3}{x^2-9}

Vertical asymptotes:

Firstly, we will factor numerator and denominator

we get

y=\frac{(x-1)(x-3)}{(x-3)(x+3)}

We can see that (x-3) is common in both numerator and denominator

so, we will only set x+3 to 0

and then we can find vertical asymptote

x+3=0

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Hole:

We can see that (x-3) is common in both numerator and denominator

so, hole will be at x-3=0

x=3

Horizontal asymptote:

We can see that degree of numerator is 2

degree of denominator is also 2

for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator

and we get

y=1

now, we can draw graph

Graph:


6 0
3 years ago
2. Determine if the expressions are equivalent by comparing the models.
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Answer:

answer 4 y +rdcmeint or 67456

Step-by-step explanation:

8 0
2 years ago
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