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Olin [163]
3 years ago
8

4 1/3 · 3/5 express your answer in simplest form. A. 2 3/5 B. 2 C. 4 1/5 D. 1 1/15

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0

Oh the answer is a I looked it up this time

Vesna [10]3 years ago
3 0

Find common denominators:

4 1/3 = 4 5/15 = 65/15

3/5 = 9/15

65/15 x 9/15 = 2.6 = 2 6/10 = 2 3/5

Final Answer:

A. 2 3/5

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Point I is on line segment HJ. Given I J equals 3X +3, HI equals 3X-1, and HJ equals 3X +8, determine the numerical length of HJ
Nezavi [6.7K]

Answer:

Step-by-step explanation:

3x + 3 + 3x - 1 = 3x + 8

6x + 2 = 3x + 8

3x + 2 = 8

3x = 6

x = 2

HJ= 3(2) + 8 =6 + 8 = 14

HI= 3(2) - 1 = 6 - 1 = 5

IJ = 3(2) + 3 = 6 + 3 = 9

4 0
3 years ago
Read 2 more answers
Rabies is an often-fatal disease typically transmitted through the bite of an infected animal. The state of Florida has been rec
slega [8]

Answer:

a) 3.6

b) 1.897

c)0.0273

d) 0.9727

Step-by-step explanation:

Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.

a)

The mean of a Poisson random variable X is μ.

mean=E(X)=μ=3.6.

b)

The  standard deviation of a Poisson random variable X is √μ.

standard deviation=S.D(X)=√μ=√3.6=1.897.

c)

The probability for Poisson random variable X can be calculated as

P(X=x)=(e^-μ)(μ^x)/x!

where x=0,1,2,3,...

So,

P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!

P(no case of rabies)=P(X=0)=0.0273.

d)

P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)

P(at least one case of rabies)=1-0.0273=0.9727

8 0
3 years ago
4b - a if a=2 b=4 find its answer
romanna [79]

Answer:

14

Step-by-step explanation:

if b=4 and a=2, then you substitute both those values into the equation, turning (4b - a) into (4*4 - 2), then you use order of operations, meaning you multiply the 4 times the 4, which turns it into 16-2, and then subtract 2 to finally reach your answer of 14.

5 0
3 years ago
Brandon sold at least 168 tickets for a carnival. He sold 4 more adult tickets than children tickets.
iris [78.8K]

Answer:

80

Step-by-step explanation:

6 0
3 years ago
Brent’s after-school game club has 12 members from which a six-member team is created. Miguel’s after-school sports club has 10
dedylja [7]

Answer:

Brent’s club has more possible team combinations because there are more members to choose from

Step-by-step explanation:

Brents club can be created in C12 6 =12!/6!/6!=7*8*9*10*11*12/(2*3*4*5*6)=

=924 variants

Miguel's  club can be created in C10 6=10!/6!/4!=7*8*9*10/(2*3*4)=210 variants

924>210 so Brent’s club has more possible team combinations because there are more members to choose from

4 0
3 years ago
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