Answer:
a) 12xy
b) 30pqr
Step-by-step explanation:
multiply the numbers and since x and y are not common terms then keep them as xy multiplied with 12
same goes with b)
If you look at the model RM is the same length as PM. PM=10 so RM=10.
Answer:
t1= 5.35
Step-by-step explanation:
Projectile height formula should be
h= -1/2gt^2+v0t+h0
where
h= height, this question asking time when "ball hit the ground" so height is 0
t= time, we look for this variable
v0= initial velocity= 85 feet/s
h0= initial height = 6 feet
g= gravity, assumed 32 feet/s^2
The calculation will be:
h= -1/2gt^2+v0t+h0
0= - 32 t^2+85t+6
0= -16t^2+85t+6
16t^2 - 85t -6 =0
x=
t=
t=
t=
t=
t1=
t1= 5.35
t2=
t2= -0.035
The answer can't be minus, so its t1
The exterior angle theorem states that an exterior angle is equal to the sum of its remote interior angles.
So...
80+20=m<CAD
m<CAD=100°