All categories

3 years ago

PLZ HELP ASAPP!!!!

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer:

It is

Step-by-step explanation:

52² = 20² + 48²

2704 = 400 + 2304

2704 = 2704

Satisfies pythagoras theorem so right angle triangle

You might be interested in

An art studio purchased a triangular plot of land in a town and constructed a new building whose base is in the shape of a right

Vinvika [58]

Answer:

The sides are 30 ft, 40 ft and 50 ft.

Step-by-step explanation:

The length of the triangle are as follows x - 4 , x + 6 and 2x - 18 . The hypotenuse should be 2x - 18 . The hypotenuse is the longest side of a right angle triangle.

Using Pythagoras theorem the length of the sides can be found.

a² + b² = c²

(x - 4)² + (x + 6)² = (2x - 18)²

(x - 4)(x - 4) + (x + 6)(x + 6) = (2x - 18)(2x - 18)

x²- 4x - 4x + 16 + x² + 6x + 6x + 36 = 4x² - 36x - 36x + 324

2x² - 8x + 12x + 16 + 36 = 4x² - 72x + 324

2x² + 4x + 52 = 4x² - 72x + 324

2x² - 4x² + 4x + 72x + 52 - 324 = 0

-2x² + 76x - 272 = 0

2x² - 76x + 272 = 0

divide through by 2

x² - 38x + 136 = 0

find the number you can multiply to give you 136 and add to give you - 38. The number are - 34 and - 4.

x² - 4x - 34x + 136 = 0

x(x - 4) - 34(x - 4) = 0

(x - 4)(x - 34 ) = 0

x = 4 or 34

we can only use 34 since using 4 will result to negative number.

x - 4 = 34 - 4 = 30 ft

x + 6 = 34 + 6 = 40 ft

2x - 18 = 68 - 18 = 50 ft

6 0

3 years ago

Please help 80 POINTS plus BRAINLIEST, THANKS AND 5 STAR

Molodets [167]

Answer:

Steps and solution in the attached picture.

Step-by-step explanation:

Steps and solution in the attached picture.

3 0

2 years ago

Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)

masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

$y=ax^2+bx+c$ ...(i)

It is passes through the point (0,11). So, substitute $x=0,y=11$ in (i).

$11=a(0)^2+b(0)+c$

$11=c$

Putting $c=11$ in (i), we get

$y=ax^2+bx+11$ ...(ii)

The quadratic function passes through the point (5,31). So, substitute $x=5,y=31$ in (ii).

$31=a(5)^2+b(5)+11$

$31-11=a(25)+5b$

$20=25a+5b$

Divide both sides by 5.

$4=5a+b$ ...(iii)

The quadratic function passes through the point (3,11). So, substitute $x=3,y=11$ in (ii).

$11=a(3)^2+b(3)+11$

$11-11=a(9)+3b$

$0=9a+3b$

Divide both sides by 3.

$0=3a+b$ ...(iv)

Subtracting (iv) from (iii), we get

$4-0=5a+b-3a-b$

$4=2a$

$\dfrac{4}{2}=a$

$2=a$

Putting $a=2$ in (iv), we get

$0=3(2)+b$

$0=6+b$

$-6=b$

Putting $a=2,b=-6$ in (ii), we get

$y=(2)x^2+(-6)x+11$

$y=2x^2-6x+11$

Therefore, the required quadratic equation is $y=2x^2-6x+11$ .

7 0

2 years ago

HELP ME PLEASE!

shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

Find the area of black circle

$r=3/2=1.5\ units$

$x=(3.14)(1.5)^{2} =7.065\ units^{2}$

Find the total area of the square target

$y=9^{2}=81\ units^{2}$

Find the probability

$P=\frac{7.065}{81}=0.0872$

Convert to percentage

$0.0872*100=8.72\%$

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

Find the area of the white portion

The area is equal to the area of the square minus the area of the circle

$x=81-7.065=73.935\ units^{2}$

Find the probability

$P=\frac{73.935}{81}=0.9128$

Convert to percentage

$0.9128*100=91.28\%$

The probability is closer to 1, because is greater than 50%

4 0

3 years ago

Is angle ABC congruent to angle DCE

xxTIMURxx [149]

Answer:

I do not think I can answer this without any pictures.

Step-by-step explanation:

Sorry, but could you attach a link or maybe sketch it out?

4 0

3 years ago

Read 2 more answers