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3 years ago

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Which is the solution set of the compound inequality 3.5 x -10> -3 and 8x -9 <39

2 answers:

aivan3 [116]3 years ago

7 0

3.5x-10>-3 add 10 to both sides

3.5x>13 divide both sides by 3.5

x>26/7

x=(26/7, +oo)

...

8x-9<39 add 9 to both sides

8x<48 divide both sides by 8

x<6

x=(-oo,6)

Since this is a compound inequality with AND the solution set will be the union of the two intervals found above.

x=(26/7, 6)

Zielflug [23.3K]3 years ago

7 0

Answer:

2<x<6

Step-by-step explanation:

I graphed it

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A student took a survey of the class. There are 42 students in the class. The student surveyed favorite foods. 10 said hamburger

8_murik_8 [283]

Answer:

52.38%

Step-by-step explanation:

Given that,

Total number of students in the class is 42

Out of 42, 10 like hamburgers, 22 like pizza, 8 like french fries, and 2 like salad.

We need to find the percentage of the class chose pizza. There are 22 student who like to have pizza. Required percentage is given by :

$P=\dfrac{22}{42}\times 100\\\\P=52.38\%$

So, 52.38% of students chose pizza.

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3 years ago

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melisa1 [442]

Answer:

-1266

Step-by-step explanation:

$(28 \times 5 - 5 \times 190) - 2 \times 228 \\ (140 - 950) - 456 \\ ( - 810) - 456 \\ - 810 - 456$

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3 years ago

A line goes through the point (2, 4) and has a slope of 3/2. Which of the following points is also on the line? CHOOSE ALL THAT

damaskus [11]

Answer:

(4,7) and (0,1)

Step-by-step explanation:

(7-4)/(4-2) = 3/ 2, and (4-1)/(2-0) = 3/2.

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3 years ago

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Fittoniya [83]

Answer:

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Step-by-step explanation:

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3 years ago

A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,

Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

So

$P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017$

Probability of a defective item being produced on the first shift:

1% of 50%. So

$P(A \cap B) = 0.01*0.5 = 0.005$

What is the probability that it was manufactured during the first shift?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941$

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0

3 years ago