It only the last one.
Hope this helps :)
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
do you want me to answer this too
Step-by-step explanation:
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Answer:
B
Step-by-step explanation:
Starting with 7,000, after 0 years there will be no increase so you still have 7,000.
The fist year you increase by 5% of 7,000.
.05x7000=350
You have a 350 increase, add that to the original 7000 to find the actual population after 1 year (domain value 1).
After 1 year: 7350
For year 2 there is an increase of 5% again, only this time we find 5% of 7350 since that was the previous years population.
.05x7350=368
Add that to previous population.
368+7350=7718
At this point so far the yearly populations have been (7000, 7350, 7718)
Answer choice B is the only one to have this progression.