1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
matrenka [14]
2 years ago
13

If y=14 when x=20, find x when y=3.5

Mathematics
1 answer:
Kruka [31]2 years ago
7 0
I hope this helps you





when y=14 x=20


y=3,5 x=?



?.14=20.3,5


?=20.3,5/14


?=5
You might be interested in
The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.
Feliz [49]
QR=9
QP=6
TU=19
TS=?
Okay so the triangles are kindred, now the equation can be made
9/16=6/x
So now we are going to cross multiply
9x=114
Now divide both sides by
912 2/3
Your answer is:
TS=12.6
4 0
3 years ago
What is 8x + -13x I just want to see if the answers are as quick as it says it is
Dafna1 [17]
- 5x. 
In case you actually want to know how I got it:
the question is just saying "8x - 13x".
8 - 13 = -5 
4 0
3 years ago
Read 2 more answers
Y is directly related to x and y is 81 when x is 27 the constant of.variation is
suter [353]

Answer:

The constant of variation is 3

Step-by-step explanation:

Given.

y=81

x=27

And y is directly related to x

y ∝ x

Here k is constant of variation

y=kx

k=\frac{y}{x}--------------(1)

Put the y and x value in equation 1.

k=\frac{81}{27}

k=3

So, the constant of variation is 3.

6 0
3 years ago
Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
I need help fast 17 points please help​
Alisiya [41]

Answer:

C f-1 (x) = x- 2

Step-by-step explanation:

The inverse is usually shown by putting a little "-1" after the function name, and reversing the units.

6 0
3 years ago
Other questions:
  • What number is to be multiplied with 1/3 to get 1/21
    13·2 answers
  • Polynomial division
    14·1 answer
  • What is tan 11pie/6 ?
    8·1 answer
  • S= 2d Solved for d <br> ——<br> T
    12·1 answer
  • How many 3 go in 76 for math
    13·2 answers
  • What is 3/5×6 please answer quickly
    8·2 answers
  • Help me please Algebra two!
    11·1 answer
  • Pls help?!?!? With this
    14·1 answer
  • To join the meeting vyv-vmvx-qnp​
    6·1 answer
  • Someone PLEASE HELP ME ASAP!!!!
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!