Answer:
30 mins
Step-by-step explanation:
<em>speed = distance/ time </em>
speed of car A
= 20/ 12 km/ min
= 5/ 3 km/ min
also, speed of car A = speed of car B
speed of car B = 5/ 3 km/ min = 50km / time taken (in mins)



=> t = 30 mins
Answer:
The rate of change of the tracking angle is 0.05599 rad/sec
Step-by-step explanation:
Here the ship is traveling at 15 mi/hr north east and
Port to Radar station = 2 miles
Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles
Therefore the ship, port and radar makes a triangle with sides
2, 7.5 and x
The value of x is gotten from cosine rule as follows
x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04
x = 6.25 miles
By sine rule we have

Therefore,

α = Angle between radar and ship α
∴ α = 58.052
Where we put
to get
and differentiate to get
= 3.208 degrees/second = 0.05599 rad/sec.
Answer:
Option C
Step-by-step explanation:

Answer: 
Step-by-step explanation:
Given:
and 
To find: 
Now as we know

So we have

Therefore d. is the correct option
Hence , 
Could you take a better picture please?