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3 years ago

I NEED HELP PLEASE HELP ME

Mathematics

1 answer:

Aloiza [94]3 years ago

5 0

Answer:
294.14cm^2

Explanation:

First find the area of the whole piece of paper:
32*14=448

Then find the area of the two semicircles, semicircle + semicircle = 1 circle:

Area of a circle= (radius squared)(pi):
(7^2)(3.14) = 153.86

Subtract the area of the two semicircles from the whole paper area:
448-153.86 = 294.14

I hope this isn’t too confusing :)

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AlladinOne [14]

Answer:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

$\hat p=0.64$ estimated proportion of interest

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

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$p_v$ represent the p value

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We want to verify if the true proportion is higher than 0.5:

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Alternative hypothesis: $p > 0.5$

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Replacing the info given we got:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

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3 years ago

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Answer:

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