A rectangle has a length of 6 cm and a width of 3 cm. Each side is doubled in length. What is the ratio of the areas of the two
2 answers:
Answer:
Ratio of the area = 4 : 1
Step-by-step explanation:
Given : A rectangle has a length of 6 cm and a width of 3 cm.Each side is doubled in length.
To find : What is the ratio of the areas of the two rectangles.
Solution : Length = 6 cm.
Width = 3 cm .
Area 1 = length * width .
Area = 6 * 3
Area 1 = 18 cm².
If the each side is double :
Length = 12 cm .
Width = 6 cm .
Area 2 = 12 * 6 .
Area 2 = 72 cm².
Ratio of the area = .
Ratio of the area = .
Ratio of the area = 4 : 1
Therefore, Ratio of the area = 4 : 1
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The length measurement of the third side of the triangular playground whose two sides are 24 ft and 30 ft long should be more than 6 but less than 54.
<h3>What is triangle inequality theorem?</h3>
Triangle inequality theorem of a triangle says that the sum of the two sides of a triangle is always greater than the third side.
Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,
(a+b)>c
(b+c)>a
(c+a)>b
There is a triangular playground. The measurements of two sides of a triangular playground are 24 feet and 30 feet.
Suppose the length of the measurement of the third side of the triangular playground is <em>c</em> meters.
As the two sides are 24 ft and 30 ft long. Thus, by the triangle inequality theorem,
For the sides 24 ft and c ft,
Thus, the length measurement of the third side of the triangular playground whose two sides are 24 ft and 30 ft long should be more than 6 but less than 54.
Learn more about the triangle inequality theorem here;