I believe it is Since the square root of 9 = 3 and the square root of 16 = 4 it is known the the square root of 12 is in between 3 and 4. Really hope this helps!
idk what a special parallelogram is but a square is most definitely a parallelogram :)
Answer:
a square is a quadrilateral but<em><u> is also a parallelogram</u></em>,rectangle and a rhombus
Step-by-step explanation:
a square is many things such as a parallelogram, a rectangle, and a rhombus.
it is a quadrilateral with all right angles and all equal sides
×║hope this helps║×
Answer:
f(2)=0
Step-by-step explanation:
f(2)=2x-4
2(2)-4
4-4
0
<span> divide a polynomial p(x) by (x-3). Add and subtract the multiple of (x-3) that has the same highest-power term as p(x), then simplify to get a smaller-degree polynomial r(x) plus multiple of (x-3). </span>
<span>The multiple of (x-3) that has x^4 as its leading term is x^3(x-3) = x^4 - 3x^3. So write: </span>
<span>x^4 + 7 = x^4 + 7 + x^3(x - 3) - x^3(x - 3) </span>
<span>= x^4 + 7 + x^3(x - 3) - x^4 + 3x^3 </span>
<span>= x^3(x - 3) + 3x^3 + 7 </span>
<span>That makes r(x) = 3x^3 + 7. Do the same thing to reduce r(x) by adding/subtracting 3x^2(x - 3) = 3x^3 - 9x^2: </span>
<span>= x^3(x - 3) + 3x^3 + 7 + 3x^2(x - 3) - (3x^3 - 9x^2) </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 </span>
<span>Again to reduce 9x^2 + 7: </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 + 9x(x - 3) - (9x^2 - 27x) </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27x + 7 </span>
<span>And finally write 27x + 7 as 27(x - 3) + 88; </span>
<span>x^4 + 7 = x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27(x - 3) + 88 </span>
<span>Factor out (x - 3) in all but the +88 term: </span>
<span>x^4 + 7 = (x - 3)(x^3 + 3x^2 + 9x + 27) + 88 </span>
<span>That means that: </span>
<span>(x^4 + 7) / (x - 3) = x^3 + 3x^2 + 9x + 27 with a remainder of 88</span>